RS Aggarwal Solutions Chapter 9 Quadrilaterals and Parallelograms Ex 9A in PDF for Free Download Question 1.Three angles of a quadrilateral measure 56°, 115° and 84°. Find the measure of the fourth angle.Solution:We know that sum of angles of a quadrilateral is 360°Now, sum of three angles = 56° + 115° + 84° = 255°Fourth angle = 360° – 255° = 105° Ans. Question 2.The angles of … [Read more...] about RS Aggarwal Solutions Class 9 Chapter 9 Quadrilaterals and Parallelograms Ex 9A

# Class 9

## RS Aggarwal Solutions Class 9 Chapter 8 Linear Equations in Two Variables Ex 8A

RS Aggarwal Solutions Chapter 8 Linear Equations in Two Variables Ex 8A in PDF for Free Download Question 1.Draw the graph of each of the following equations.(i) x = 5(ii) y = – 2(iii) x + 6 = 0(iv) x + 7 = 0(v) y = 0(vi) x = 0Solution:(i) x = 5 is the line AB parallel to the y-axis at a distance of 5 units.(ii) y = – 2 is the line CD parallel to x-axis at a distance of – 2 … [Read more...] about RS Aggarwal Solutions Class 9 Chapter 8 Linear Equations in Two Variables Ex 8A

## RS Aggarwal Solutions Class 9 Chapter 7 Areas Ex 7A

RS Aggarwal Solutions Chapter 7 Areas Ex 7A in PDF for Free Download Question 1.Find the area of the triangle whose base measures 24 cm and the corresponding height measures 14.5 cm.Solution:Base of the triangle (b) = 24cm and height (h) = 14.5 cm∴ Area = x b x h = x 24 x 14.5 cm²= 174 cm² Ans. Question 2.The base of triangular field is three times its altitude. If the cost … [Read more...] about RS Aggarwal Solutions Class 9 Chapter 7 Areas Ex 7A

## RS Aggarwal Solutions Class 9 Chapter 6 Coordinate Geometry Ex 6A

RS Aggarwal Solutions Class 9 Chapter 6 Coordinate Geometry Ex 6A in PDF for Free Download Question 1.Write down the coordinates of each of the points A, B, C, D, E shown below :Solution:Co-ordinates ofA are ( – 6, 5)B are (5, 4)C are ( – 3, 2)D are (2, – 2)E are ( – 1, – 4)Ans. Question 2.Draw the lines X'OX and YOY' as the coordinates axes on a paper and plot the following … [Read more...] about RS Aggarwal Solutions Class 9 Chapter 6 Coordinate Geometry Ex 6A

## RS Aggarwal Solutions Class 9 Chapter 5 Congruence of Triangles and Inequalities in a Triangle Ex 5A

RS Aggarwal Solutions Class 9 Chapter 5 Congruence of Triangles and Inequalities in a Triangle Ex 5A in PDF for Free Download Question 1.In a ∆ ABC, if AB = AC and ∠ A = 70°, find ∠B and ∠C.Solution:In ∆ ABC, ∠A = 70° and AB = AC (given)∴ ∠C = ∠B(Angles opposite to equal sides)But ∠A + ∠B + ∠C = 180°(Sum of angles of a triangle)=> 70° + ∠B + ∠B = 180°(∴ ∠B = ∠C)=> … [Read more...] about RS Aggarwal Solutions Class 9 Chapter 5 Congruence of Triangles and Inequalities in a Triangle Ex 5A

## RS Aggarwal Solutions Class 9 Chapter 4 Lines and Triangles Ex 4C

RS Aggarwal Solutions Class 9 Chapter 4 Lines and Triangles Ex 4C in PDF for Free Download Question 1.In the adjoining figure, AB || CD are cut by a transversal t at E and Frespectively. If ∠1 = 70°, End the measure of each of the remaining marked angles.Solution:AB || CD and a line t intersects them at E and F forming angles ∠1, ∠ 2, ∠3, ∠4, ∠5, ∠6, ∠7 and ∠8. Question 2.In … [Read more...] about RS Aggarwal Solutions Class 9 Chapter 4 Lines and Triangles Ex 4C

## RS Aggarwal Solutions Class 9 Chapter 4 Lines and Triangles Ex 4D

RS Aggarwal Solutions Class 9 Chapter 4 Lines and Triangles Ex 4D in PDF for Free Download Question 1.In ∆ABC, if ∠B = 76° and ∠C = 48°, find ∠ASolution:In ∆ABC,∠B = 76° and ∠C = 48°But ∠A + ∠B + ∠C = 180°(Sum of angles of a triangle)=> ∠A + 76° + 48° = 180°=> ∠ A + 124° = 180°=> ∠A= 180° – 124° = 56° Question 2.The angles of a triangle are in the ratio 2:3:4. Find the … [Read more...] about RS Aggarwal Solutions Class 9 Chapter 4 Lines and Triangles Ex 4D

## RS Aggarwal Solutions Class 9 Chapter 4 Lines and Triangles Ex 4B

RS Aggarwal Solutions Class 9 Chapter 4 Lines and Triangles Ex 4B in PDF for Free Download Question 1.In the adjoining figure, AOB is a straight line. Find the value of x.Solution:AOB is a straight line∠AOC + ∠BOC = 180° (Linear pair)=> 62° + x= 180°=> x = 180° – 62°=> x = 118°Hence, x = 118° Ans. Question 2.In the adjoining figure, AOB is a straight line. Find the … [Read more...] about RS Aggarwal Solutions Class 9 Chapter 4 Lines and Triangles Ex 4B

## RS Aggarwal Solutions Class 9 Chapter 4 Lines and Triangles Ex 4A

RS Aggarwal Solutions Class 9 Chapter 4 Lines and Triangles Ex 4A in PDF for Free Download Question 1.Define the following terms.(i) Angle(ii) Interior of an angle(iii) Obtuse angle(iv) Reflex angle(v) Complementary angles(vi) Supplementary anglesSolution:(i)Angle : When two rays OA and OB meet at a point o, then ∠AOB is called an angle.(ii) Interior of angle : The interior an … [Read more...] about RS Aggarwal Solutions Class 9 Chapter 4 Lines and Triangles Ex 4A

## RS Aggarwal Solutions Class 9 Chapter 3 Introduction to Euclid’s Geometry Ex 3A

RS Aggarwal Solutions Class 9 Chapter 3 Introduction to Euclid's Geometry Ex 3A in PDF for Free Download Question 1.What is the difference between a theorem and an axiom.Solution:A theorem is a statement that requires a proof while an axiom is the basic fact which is taken for granted without proof. Question 2.Define the following terms :(i) Line segment(ii) Ray(iii) … [Read more...] about RS Aggarwal Solutions Class 9 Chapter 3 Introduction to Euclid’s Geometry Ex 3A